Can I just do 1/2 m*v^2 = modes.velocities, assuming parabolic dispersion?
On Mon, Jan 23, 2017 at 3:13 PM, Harshad Sahasrabudhe
Hi,
You could do that, but this is already done in Kwant, and you can read the
velocities off from the modes object [1].
I was able to obtain the velocities from the modes object. I confirmed that modes.velocities is just the inverse of integral |đ|2 over the unit cell. If I did the math correctly, I got the units of modes.velocities to be eV (energy units of my Hamiltonian). How can I convert this to lets say m/s?
Thanks, Harshad
On Mon, Jan 23, 2017 at 10:18 AM, Harshad Sahasrabudhe < hsahasra@purdue.edu> wrote:
Great, thanks a lot!
On Mon, Jan 23, 2017 at 10:15 AM, Anton Akhmerov < anton.akhmerov+kd@gmail.com> wrote:
Thank you. Then to calculate the velocity, should I just divide the probability current by the integral of |đ|2 over the unit cell?
You could do that, but this is already done in Kwant, and you can read the velocities off from the modes object [1].
Best, Anton
[1]: https://kwant-project.org/doc/1/reference/generated/kwant.ph ysics.PropagatingModes#kwant.physics.PropagatingModes