systems. You can find the code over here (if you don't want to download it
Thanks for your reply.
In the kwant paper, I think fig 7 indicates ~1000GB memory is needed for such a system. Also, I only replicated my unit cell twice in the y direction. It seems that I need to figure out some tricks to work around this.
Anton reminded me of a workaround written by Christoph for dealing with periodic
From: Joseph Weston <firstname.lastname@example.org>
Sent: Wednesday, May 11, 2016 9:53 PM
To: Chong Wang
Subject: Re: [Kwant] scatter without a center areathat the memory requirement for solving this sort of size should be ~ 100GB.
Ok, now it certainly makes sense that the memory blows up; the kwant paper indicates
`lead.cell_hamiltonian()` gives 32000. The thickness of my slab is 50. Is this something not possible to calculate?