Hi,
I don't quite understand what 'having the same symmetry' means in this context.
For example, everything works fine for on-site random potential, which doesn't have the 1D translationnal symmetry in the unit cell, but Kwant makes the hamiltonian such that the symmetry with respect to the cells separated by a symmetry vector is valid.
So, this does work for on-site random term but not for the hoppings ? (it also doesn't work for random real nearest neighbors hopping terms)
I will try to fix it by hand, by specifying the hopping terms between the cells, and see if it works.
Best regards,
Alexandre
De: "Abbout Adel" <abbout.adel@gmail.com>
À: "alexandre bernard1" <alexandre.bernard1@u-psud.fr>
Cc: "kwant-discuss" <kwant-discuss@kwant-project.org>
Envoyé: Samedi 19 Mai 2018 23:21:02
Objet: Re: [Kwant] Hamiltonian not hermician for an infinite wire with random complex hopping
In the documentation, it is mentioned that the function defining the potential in the lead should have the same symmetry as the lead which is obviously not fulfilled with your random function.
Another thing, you need to be careful when you define your unit cell in the lead (or in your system with the translational symmetry). If you define a larger unit cell, the translational symmetry will make the sites doubled.
The last thing I would like to comment is that when you have a system with random sites, you can not pretend to have a continuous spectrum (or disjoint bands). In fact, from random matrix theory, we know that usually the eigenvalues are repelling each other and the probability to get two eigenvalues close to each other tends to zero. So, I suspect that, more likely you will have a spectrum composed by disjoint points rather than bands.
I hope this helps.
Adel