Exporting subscribers list
Hello, there!
I am using MailMain trough its web-based interface. I don't have access to the server where its runs, because it's a third-party hosting company which provides me the MailMan service.
I want to export the subscribers list in a format like this:
subscriber1@mydomain.com subscriber2@mydomain.com . . . . . . . subscriber9@mydomain.com
I wasn't able to find the way to perform this operation, searching deeply into the options tree.
Is it possible to obtain this kind of list?
T.I.A.
-- Arlequín _o) amahoro_AT_adinet_DOT_com_DOT_uy / \\ http://counter.li.org/ _(___V Linux Registered User #207262
On Fri, Nov 19, 2004 at 01:52:36PM -0300, Arlequín wrote:
I am using MailMain trough its web-based interface. I don't have access to the server where its runs, because it's a third-party hosting company which provides me the MailMan service.
I want to export the subscribers list in a format like this:
subscriber1@mydomain.com subscriber2@mydomain.com
mailman-subscribers.py is example program showing how you can get that sort of list through the web interface. It is available from; <http://starship.python.net/crew/jwt/mailman/#throughtheweb>
-- Jim Tittsler http://www.OnJapan.net/ GPG: 0x01159DB6 Python Starship http://Starship.Python.net/ Ringo MUG Tokyo http://www.ringo.net/rss.html
Hello.
I am tring your mailman-subscribers.py script using ActiveState Python 2.4 with ClientCookie enabled.
I am trying to fetch the subscribers list from my WindowsXP box to a hosting service where I have 2000+ subscribers I type:
python.exe mailman-subscribers.py -v sg-guarani.org newsletter mypassword
And I get a 0....
What am I doing wrong?
Thanks in advance.
On 19/11/2004 21:35, Jim Tittsler wrote:
On Fri, Nov 19, 2004 at 01:52:36PM -0300, Arlequín wrote:
I am using MailMain trough its web-based interface. I don't have access to the server where its runs, because it's a third-party hosting company which provides me the MailMan service.
I want to export the subscribers list in a format like this:
subscriber1@mydomain.com subscriber2@mydomain.com
mailman-subscribers.py is example program showing how you can get that sort of list through the web interface. It is available from; <http://starship.python.net/crew/jwt/mailman/#throughtheweb>
-- Arlequín _o) amahoro_AT_adinet_DOT_com_DOT_uy / \\ http://counter.li.org/ _(___V Linux Registered User #207262
Arlequín wrote:
I am tring your mailman-subscribers.py script using ActiveState Python 2.4 with ClientCookie enabled.
I am trying to fetch the subscribers list from my WindowsXP box to a hosting service where I have 2000+ subscribers I type:
python.exe mailman-subscribers.py -v sg-guarani.org newsletter mypassword
And I get a 0....
Granted the script should be more robust, but it's only an example...
First, what version of mailman-subscribers.py do you have? The latest is 2005-06-14. There have been at least 5 revisions since November 2004.
The current version when run with the -v option emits '0(0)' as it retrieves the first page of the member list and then perhaps 'a(0)' as it gets the first page of 'a' and 'a(1)' for the second page of a and so on.
I can make it emit '0(0)' and nothing more if I misspell the listname or the list password, but I am running the latest version with Python 2.4.1 so it uses Python's cookielib instead of ClientCookie. I seem to remember that -v used to work differently, but I don't recall the details and no longer have any old versions.
If you literally mean it prints '0' and then slowly adds '.', it is probably printing one '.' per page of admin_member_chunksize or less members which would be 70+ dots for 2000+ members with the standard default of 30 for admin_member_chunksize.
-- Mark Sapiro <msapiro@value.net> The highway is for gamblers, San Francisco Bay Area, California better use your sense - B. Dylan
I've found that I can get a membership list via email: I send a message to
mylist-requrest@mydomain.comThe message consists of "who admin-password"
I get a full listing back of all non-hidden members. I've set all my lists to default to non-hidden. You would need to reformat the text of the list you receive, because it includes real names if given.
On 11/19/04 8:52 AM, "Arlequín" <amahoro@adinet.com.uy> wrote:
Hello, there!
I am using MailMain trough its web-based interface. I don't have access to the server where its runs, because it's a third-party hosting company which provides me the MailMan service.
I want to export the subscribers list in a format like this:
subscriber1@mydomain.com subscriber2@mydomain.com . . . . . . . subscriber9@mydomain.com
I wasn't able to find the way to perform this operation, searching deeply into the options tree.
Is it possible to obtain this kind of list?
T.I.A.
-- Your companion on the journey, Allen Watson
The Circle of Atonement, P.O. Box 4238, W. Sedona, AZ 86340 <http://www.circleofa.com> "Whom you forgive is free, and what you give you share. Forgive the sins your brother thinks he has committed, and all the guilt you think you see in him." (A Course in Miracles, T-19.IV(D.i).15:9-10)
participants (4)
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Allen Watson -
Arlequín -
Jim Tittsler -
Mark Sapiro