Hi,
I'm completely new to this list (and fairly new to numpy in general), but I was wondering if you tried multiplying the bool array and the original array.
Try:
x=array([[0,1,2],[3,4,5],[6,7,8]])
if rank(x) <= 1
dot(x>=1, x)
else
(x>=1)*x
This will give you a completely numerical array of the same structure, but all numbers less than 1 will be zero fo easy handling. Is this what you're trying to accomplish?
--
Derek
On Thu, Mar 15, 2012 at 08:35, jonasr
<jonas.ruebsam@web.de> wrote:
Hello,
my problem is that i want to remove some small numbers of an 2d array,
for example if i want to sort out all numbers smaller then 1 of an array i
get
x=[[0,1,2],[3,4,5][6,7,8]]
c=x>=1
In [213]: c
Out[213]:
array([[False, True, True],
[ True, True, True],
[ True, True, True]], dtype=bool)
In [214]: x[c]
Out[214]: array([1, 2, 3, 4, 5, 6, 7, 8])
the problem ist that i now have a 1d array, is there any possibility to
keep the 2d structure ?
greets jonas
--
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