On 8 Sep 2014 10:42, "Sturla Molden" <sturla.molden@gmail.com> wrote:

>

> Stefan Otte <stefan.otte@gmail.com> wrote:

>

> > stack([[a, b], [c, d]])

> >

> > In my case `stack` replaced `hstack` and `vstack` almost completely.

> >

> > If you're interested in including it in numpy I created a pull request

> > [1]. I'm looking forward to getting some feedback!

>

> As far as I can see, it uses hstack and vstack. But that means a and b have

> to have the same number of rows, c and d must have the same rumber of rows,

> and hstack((a,b)) and hstack((c,d)) must have the same number of columns.

>

> Thus it requires a regularity like this:

>

> AAAABB

> AAAABB

> CCCDDD

> CCCDDD

> CCCDDD

> CCCDDD

>

> What if we just ignore this constraint, and only require the output to be

> rectangular? Now we have a 'tetris game':

>

> AAAABB

> AAAABB

> CCCCBB

> CCCCBB

> CCCCDD

> CCCCDD

>

> or

>

> AAAABB

> AAAABB

> CCCCBB

> CCCCBB

> CCCCBB

> CCCCBB

>

> This should be 'stackable', yes? Or perhaps we need another stacking

> function for this, say numpy.tetris?

It's not at all obvious to me how to describe such "tetris" configurations, or interpret then unambiguously. Do you have a more detailed specification in mind?

> And while we're at it, what about higher dimensions? should there be an

> ndstack function too?

Same comment here.

-n