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Aug. 30, 2006
6:39 p.m.
Hello, I would like to discuss the following code: #***start*** import numpy as N a = N.array((200), dtype = N.uint8) print (a * 100) / 100 b = N.array((200, 200), dtype = N.uint8) print (b * 100) / 100 #***stop*** The first print statement will print "200" because the uint8-value is cast "upwards", I suppose. The second statement prints "[0 0]". I suppose this is due to overflows during the calculation. How can I tell numpy to do the upcast also in the second case, returning "[200 200]"? I am interested in the fastest solution regarding execution time. In my application I would like to store the result in an Numeric.UInt8-array. Thanks for every comment Lars