Re: [Numpy-discussion] probably simple, reverse a reshape...

Feb. 23, 2009


      John [H2O] wrote:
...
Hello, this is probably one of those questions that is going to seem
simple after reading responses...
and a few more minutes of thinking:
def row2shape(row,a):
      """ to get indices a 2d array row# to the 3d array 
      from which it was reshaped. ""
      d0,d1,d2 = a.shape;
      nd0 = row/d1;
      nd1 = (row-(nd0*d1));
      return nd0,nd1

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