Thanks for the precise explanation that make things clearer. In fact, the example I gave was mainly to illustrate my question in the quickest way. Concerning the dtype argument during array creation, I thought it was here for somehow controlling the type of array elements. For example, if I use a "regular" numpy array (let's say a float array), I cannot set an item to a string value (it raises a ValueError: setting an array element with a sequence). So what would be the best way to use numpy arrays with "foreign" types (or is it possible at all) ? I've designed the "real" Unit in C++ and exported it to python (via boost and shared pointers) and I would like to create array of such Units (in fact, I also created an array-like class but I would prefer to use directly the real array interface to benefit from the great work of numpy instead of re-inventing the wheel). Ideally, I would like to be able to write z = N.array (a, dtype=Unit) and would expect numpy to make a copy of the array by calling my type with each element of a. Then, if my type accepts the argument during creation, everything's fine, else it raises an error. Nicolas On Thu, 2008-07-10 at 13:43 -0700, Christopher Barker wrote:
Nicolas Rougier wrote:
I would like to create numpy array with my own (python) datatype, so I tried the obvious solution:
from numpy import * class Unit(object): def __init__(self,value=0.0): self.value = value def __float__(self): return self.value def __repr__(self): return str(self.value)
a = array (array([[1,2],[3,4]]), dtype=Unit)
the dtype argument is designed to take a numpy type object, not an arbitrary class -- what you want in this case is dtype=numpy.object, which is what you did before. I'm a surprised this didn't raise an error, but it looks like you got an object array, but you objects you gave it are python integers. All python classes are "objects" as far an numpy is concerned. The numpy dtypes are a description of a given number of bytes in memory -- python classes are stored as a pointer to the python object.
(and you really don't want to use "import *")
Also, the commented line (a[0,0] = 0) makes the item to become an int while I need to set the value of the item instead, is that possible ?
a[0,0] = Unit(0)
You're setting the [0,0]th element to an object, you need to give it the object you want, the literal "0" is a python integer with the value zero.
numpy arrays of python objects act a whole lot like other python containers. What would you expect from :
a = [1,2,3,4]
a list of integers, no?
or
a = [Unit(1), Unit(2)]
# a list of Units..
then
# a[0] = 3
now a list with the integer3 in the zeroth position, and a Unit in the 1st.
You did it right the first time:
a = array([[Unit(1), Unit(2)], [Unit(3), Unit(4)]])
though you need to be careful building object arrays of nested lists -- numpy won't unnecessarily figure out how do d-nest it. You might want to do:
import numpy as np a = np.empty((2,2), np.object) a array([[None, None], [None, None]], dtype=object) a[:,:] = [[Unit(1), Unit(2)], [Unit(3), Unit(4)]] a array([[1, 2], [3, 4]], dtype=object)
One more note:
class Unit(object): def __init__(self,value=0.0): self.value = value def __float__(self): return self.value def __repr__(self): return str(self.value)
__repr__ really should be something like: def __repr__(self): return "Unit(%g)%self.value"
eval(repr(Object)) == Object, ideally, plus it'll be easier to debug if you can see what it is.
-Chris