Re: [Numpy-discussion] efficient use of numpy.where() and .any()

24 Apr 2007


      Mark.Miller wrote:
...
Pierre GM wrote:
...
...
a[a<0] = numpy.random.normal(0,1)
This is a neat construct that I didn't realize was possible.  However, 
it has the undesirable (in my case) effect of placing a single new 
random number in each locations where a<0.  While this could work, I 
ideally need a different random number chosen for each replaced value. 
Does that make sense?
Certainly. How about this?
mask = (a<0)
a[mask] = numpy.random.normal(0, 1, size=mask.sum())
-- 
Robert Kern

"I have come to believe that the whole world is an enigma, a harmless enigma
 that is made terrible by our own mad attempt to interpret it as though it had
 an underlying truth."
  -- Umberto Eco