If you really need to pass the function name : In [3]: def my_func(x): ...: return 2*x In [4]: def caller(fname,x): ...: return eval("%s(%f)"%(fname,x)) In [5]: caller("my_func",2) Out[5]: 4.0 On 10/20/2010 03:46 PM, Zachary Pincus wrote:
I'm trying to write an implementation of the amoeba function from numerical recipes and need to be able to pass a function name and parameter list to be called from within the amoeba function. Simply passing the name as a string doesn't work since python doesn't know it is a function and throws a typeerror. Is there something similar to IDL's 'call_function' routine in python/numpy or a pythonic/numpy means of passing function names?
Just pass the function itself! For example:
def foo(): print 6
def call_function_repeatedly(func, count): for i in range(count): func()
call_function_repeatedly(foo, 2) # calls foo twice
bar = foo bar() # still calls foo... we've just assigned the function to a different name
In python, functions (and classes, and everything else) are first- class objects and can be assigned to variables, passed around, etc, etc, just as anything else.
However, note that scipy.optimize.fmin implements the Nelder-Mead simplex algorithm, which is (I think) the same as the "amoeba" optimizer. Also you might be interested in the openopt package, which implements more optimizers a bit more consistently than scipy.optimize.
Zach _______________________________________________ NumPy-Discussion mailing list NumPy-Discussion@scipy.org http://mail.scipy.org/mailman/listinfo/numpy-discussion