Here is the for loop that I am think about. Also, I do not know whether the where commands can handle the complicated logic.
The where command basically find the data in the square around the point cnstl[j].
 
Let the data array is qam with size N
 
Out = X
error = X
for i in arange(N):
    for j in arange(L):
         aa = np.where((real(X)<real(cnstl[j])+1) & (real(X)>real(cnstl[j])-1) & (imag(X)<imag(cnstl[j])+1) & (imag(X)>imag(cnstl[j]-1))
         Out[aa]=cnstl[j]
         error[aa]=abs(X)**2 - abs(cnstl[j])**2
 
 
Thanks
 
Frank

> Date: Wed, 28 Jan 2009 23:57:16 -0600
> From: robert.kern@gmail.com
> To: numpy-discussion@scipy.org
> Subject: Re: [Numpy-discussion] help on fast slicing on a grid
>
> On Wed, Jan 28, 2009 at 23:52, frank wang <f.yw@hotmail.com> wrote:
> >
> > Hi,
> >
> > I have to buidl a grid with 256 point by the command:
> > a = arange(-15,16,2)
> > L = len(a)
> > cnstl = a.reshape(L,1)+1j*a
> >
> > My problem is that I have a big data array that contains the data round the
> > points in cnstl. I want to slice the point to the closest cnstl point and
> > also compute the error. The condition is in the middle of the two point in x
> > and y axis. I can do it in a for loop. Since Python and numpy have a lot of
> > magic, I want to find an efficient way to do. This problem arise from QAM
> > 256 modulation.
>
> Can you show us the for loop? I'm not really sure what you want to compute.
>
> --
> Robert Kern
>
> "I have come to believe that the whole world is an enigma, a harmless
> enigma that is made terrible by our own mad attempt to interpret it as
> though it had an underlying truth."
> -- Umberto Eco
> _______________________________________________
> Numpy-discussion mailing list
> Numpy-discussion@scipy.org
> http://projects.scipy.org/mailman/listinfo/numpy-discussion

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