No, the nth index of a Python sequence is a[n], where n starts from zero. Thus, if I want the nth dimension of array a, I want a.shape[n].
I reverted the page to its original form and added a couple explanatory comments about zero vs one based indexing.
now there is MATLAB NDArray Matrix size(a,n) a.shape[n] a.shape[n]
but it should be size(a,n) a.shape[n-1] a.shape[n-1]
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