Warren Weckesser <warren.weckesser@gmail.com> wrote:
0 if x < 0
heaviside(x) = 0.5 if x == 0
1 if x > 0
This is not correct. The discrete form of the Heaviside step function has
the value 1 for x == 0.
heaviside = lambda x : 1 - (x < 0).astype(int)
Sturla
