[Numpy-discussion] handling of inf

Hi, I was wondering if the numpy function 'isinf' should return True for complex infinity. I encountered the following behavior that could be considered a bug:

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import numpy as N N.isinf(1j*N.inf) True

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1j/(N.array(1)-1) (nannanj) N.isinf(1j/(N.array(1)-1)) False

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1j/(N.array([1])-1) array([ nan +nanj]) N.isinf(1j/(N.array([1])-1)) array([False], dtype=bool)

Thanks, Kilian -- Kilian Koepsell Redwood Center for Theoretical Neuroscience Helen Wills Neuroscience Institute, UC Berkeley 132 Barker Hall, #3190, Berkeley, CA 94720-3190