On Mon, 5 Feb 2007, Timothy Hochberg wrote:

> On 2/5/07, Hanno Klemm <klemm@phys.ethz.ch> wrote:
> [numpy.fft[
>
>     The packing of the result is "standard": If A = fft(a, n), then A[0]
> >     contains the zero-frequency term, A[1:n/2+1] contains the
> >     positive-frequency terms, and A[n/2+1:] contains the
> > negative-frequency
> >     terms, in order of decreasingly negative frequency. So for an 8-point
> >     transform, the frequencies of the result are [ 0, 1, 2, 3, 4, -3,
> > -2, -1].
>
>
> [scipy.fft]
>
>
>       f = [0,1,...,n/2-1,-n/2,...,-1]/(d*n)         if n is even
> >       f = [0,1,...,(n-1)/2,-(n-1)/2,...,-1]/(d*n)   if n is odd
> >
> > >>>
> >
> > So one claims, that the packing goes from [0,1,...,n/2,-n/2+1,..,-1]
> > (fft) and the other one claims the frequencies go from
> > [0,1,...,n/2-1,-n/2,...-1]
> >
> > Is this inconsistent or am I missing something here?
>
>
> Both, I think.
>
> In the even case, the frequency at n/2 is shared by both the positive
> frequencies, so for that case things are consistent if not terribly clear.
> For the odd case, this is not true, and the scipy docs look correct in this
> case, while the numpy docs appear to assign an extra frequency to the
> positive branch. Of course that's not the one you were complaining about
> ;-).

Extra frequency where?

(numpy 1.0, debian sarge)
>>> n=9
>>> A=arange(n)

numpy docs:
>>> A[1:n/2+1]
array([1, 2, 3, 4])
>>> A[n/2+1:]
array([5, 6, 7, 8])

scipy docs:
>>> (n-1)/2
4
>>> -(n-1)/2
-4

Note that in the odd-n case, there is no Nyquist term.  If
F = fft(f), len(f) == 9
then F[-4] != F[4] (F[5] == F[-4] by periodicty in frequency)