If you are using integers, why not use Python's Long? Colin W. On 11/10/2011 2:00 PM, Matthew Brett wrote:
Hi,
Can anyone think of a clever way to round an integer to the next lowest integer represented in a particular floating point format?
For example:
In [247]: a = 2**25+3
This is out of range of the continuous integers representable by float32, hence:
In [248]: print a, int(np.float32(a)) 33554435 33554436
But I want to round down (floor) the integer in float32. That is, in this case I want:
floor_exact(a, np.float32) 33554432
I can break the float into its parts to do it:
https://github.com/matthew-brett/nibabel/blob/f687bfc88d1676a09fc76c968a346b...
but that's obviously rather ugly... Is there a simpler way? I'm sure there is and I haven't thought of it...
Best,
Matthew _______________________________________________ NumPy-Discussion mailing list NumPy-Discussion@scipy.org http://mail.scipy.org/mailman/listinfo/numpy-discussion