me!
I have two cases.
- I need that arctan2(1+0.00000001j,1-0.000001j) gives something close to arctan2(1,1): any decent analytic prolungation will do!
- if someone of you is familiar with electromagnetic problems, in particular with Snell's law, will recognize that in case of
total internal reflection the wavevector tangential to the interface is real, while the normal one is purely imaginary: hence the angle of diffraction is still given by arctan2(k_tangent, k_normal), that, as in Matlab or Octave, should give pi/2 (that physically means no propagation -- total internal reflection, as said).
L.
On 4/30/07, Anne Archibald <peridot.faceted@gmail.com> wrote:
On 29/04/07, David Goldsmith <David.L.Goldsmith@noaa.gov> wrote:
> Far be it from me to challenge the mighty Wolfram, but I'm not sure that
> using the *formula* for calculating the arctan of a *single* complex
> argument from its real and imaginary parts makes any sense if x and/or y
> are themselves complex (in particular, does Lim(formula), as the
> imaginary part of complex x and/or y approaches zero, approach
> arctan2(realpart(x), realpart(y)?) - without going to the trouble to
> determine it one way or another, I'd be surprised if "their"
> continuation of the arctan2 function from RxR to CxC is (a. e.)
> continuous (not that I know for sure that "mine" is...).
Well, yes, in fact, theirs is continuous, and in fact analytic, except
along the branch cuts (which they describe). Formulas almost always
yield continuous functions apart from easy-to-recognize cases. (This
can be made into a specific theorem if you're determined.)
Their formula is a pretty reasonable choice, given that it's not at
all clear what arctan2 should mean for complex arguments. But for
numpy it's tempting to simply throw an exception (which would catch
quite a few programmer errors that would otherwise manifest as
nonsense numbers). Still, I suppose defining it on the complex numbers
in a way that is continuous close to the real plane allows people to
put in almost-real complex numbers and get out pretty much the answer
they expect. Does anyone have an application for which they need
arctan2 of, say, (1+i,1-i)?
Anne
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