Thanks Paul. I suppose this is now going slightly out of bounds for f2py. What I am looking for is the fortran kind type for a byte. I thought that this was int8. I guess the question is how to identify the kind type. Although I have verified that integer(1) seems to work for me, I would really like to know why and your answer alludes to that. Please excuse my ignorance on this topic. Can you perhaps educate me a little on 'literal kind values'? I take you to mean that 'int8' is not a literal kind value while 1 and 8 are examples of literal kind values. Thanks, John On Tue, Apr 17, 2012 at 10:12 AM, Paul Anton Letnes < paul.anton.letnes@gmail.com> wrote:
Ah, come to think of it, I think that f2py only supports literal kind values. Maybe that's your problem.
Paul
On 17. apr. 2012, at 07:58, Sameer Grover wrote:
On Tuesday 17 April 2012 11:02 AM, John Mitchell wrote:
Hi,
I am using f2py to pass a numpy array of type numpy.int8 to fortran. It seems like I am misunderstanding something because I just can't make it work.
Here is what I am doing.
PYTHON b=numpy.array(numpy.zeros(shape=(10,),dtype=numpy.int8),order='F') b[0]=1 b[2]=1 b[3]=1 b array([1, 0, 1, 1, 0, 0, 0, 0, 0, 0], dtype=int8)
FORTRAN subroutine print_bit_array(bits,n) use iso_fortran_env integer,intent(in)::n integer(kind=int8),intent(in),dimension(n)::bits print*,'bits = ',bits end subroutine print_bit_array
RESULT when calling fortran from python bits = 1 0 0 0 0 0 0 0 1 0
Any Ideas? thanks, John
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NumPy-Discussion@scipy.org http://mail.scipy.org/mailman/listinfo/numpy-discussion It seems to work if "integer(kind=int8)" is replaced with "integer(8)" or "integer(1)". Don't know why, though.
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