Hi Olivier, No that does not seem to do anything am I missing another step whereever b is greater than a replace b with a? thanks On Wed, Dec 7, 2011 at 11:55 AM, Olivier Delalleau <shish@keba.be> wrote:
It may not be the most efficient way to do this, but you can do: mask = b > a a[mask] = b[mask]
-=- Olivier
2011/12/6 questions anon <questions.anon@gmail.com>
I would like to produce an array with the maximum values out of many (10000s) of arrays. I need to loop through many multidimentional arrays and if a value is larger (in the same place as the previous array) then I would like that value to replace it.
e.g. a=[1,1,2,2 11,2,2 1,1,2,2] b=[1,1,3,2 2,1,0,0 1,1,2,0]
where b>a replace with value in b, so the new a should be :
a=[1,1,3,2] 2,1,2,2 1,1,2,2]
and then keep looping through many arrays and replace whenever value is larger.
I have tried numpy.putmask but that results in TypeError: putmask() argument 1 must be numpy.ndarray, not list Any other ideas? Thanks
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