On Thu, 22 Sep 2005, Andrea Riciputi apparently wrote:
I've already tried something like this, but it doesn't work since f1 and f2 return not valid values outside the range over they are defined. Perhaps an example could clarify; suppose that f1(x) = 1./ sqrt(1 - x**2) for x <= 1, and f2(x) = 1./sqrt(x**2 - 1) for x > 1.
Your suggestion, as the other I've tried, fails with a "OverflowError: math range error".
If you do it as I suggested, they should not I believe be evaluated outside of their range. So your function must be generating an overflow error within this range.
import math import random def f1(x): return math.sqrt(1-x**2) ... def f2(x): return 1./math.sqrt(x**2-1) ... def f(x): return x<=1 and f1(x) or f2(x) ... d = [random.uniform(0,2) for i in range(20)] fd = [f(x) for x in d]
Works fine. Cheers, Alan Isaac