Hi,

On Sun, Sep 9, 2012 at 12:56 AM, nicky van foreest <vanforeest@gmail.com> wrote:
Hi,

I ran the following code:

        args = np.array([4,8])
        print np.sum( (arg > 0) for arg in args)
        print np.sum([(arg > 0) for arg in args])
        print np.prod( (arg > 0) for arg in args)
        print np.prod([(arg > 0) for arg in args])
Can't see why someone would write code like above, but anyway:
In []: args = np.array([4,8])
In []: print np.sum( (arg > 0) for arg in args)
2
In []: print np.sum([(arg > 0) for arg in args])
2
In []: print np.prod( (arg > 0) for arg in args)
<generator object <genexpr> at 0x062BDA08>
In []: print np.prod([(arg > 0) for arg in args])
1
In []: print np.prod( (arg > 0) for arg in args).next()
True
In []: sys.version
Out[]: '2.7.2 (default, Jun 12 2011, 15:08:59) [MSC v.1500 32 bit (Intel)]'
In []: np.version.version
Out[]: '1.6.0'

My 2 cents,
-eat 

with this result:

2
1
<generator object <genexpr> at 0x1c70410>
1

Is the difference between prod and sum intentional? I would expect
that  numpy.prod would also work on a generator, just like numpy.sum.

BTW: the last line does what I need: the product over the truth values
of all elements of args. Is there perhaps a nicer (conciser) way to
achieve this?  Thanks.

Nicky
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