Matthieu Brucher <matthieu.brucher <at> gmail.com> writes:
Little correction, only c[(2,3)] gives me what I expect, not c[[2,3]], which is even stranger.
c[(2,3)] is the same as c[2,3] and obviously works as you expected. c[[2,3]] is refered to as 'advanced indexing' in the numpy book. It will return elements 2 and 3 along the first dimension. To get what you want, you need to put it like this: c[[2],[3]] In [118]: c = N.arange(0.,3*4*5).reshape((3,4,5)) In [119]: c[[2],[3]] Out[119]: array([[ 55., 56., 57., 58., 59.]]) This does not work however using a ndarray holding the indices. In [120]: ind = N.array([[2],[3]]) In [121]: c[ind] --------------------------------------------------------------------------- <type 'exceptions.IndexError'> Traceback (most recent call last) /media/hda6/home/ck/<ipython console> in <module>() <type 'exceptions.IndexError'>: index (3) out of range (0<=index<=2) in dimension 0 so you have to convert it to a list before: In [122]: c[ind.tolist()] Out[122]: array([[ 55., 56., 57., 58., 59.]]) Christian