5 Oct
2007
5 Oct
'07
2:05 p.m.
John Hunter wrote:
On 9/26/07, Robert Kern robert.kern@gmail.com wrote:
Here is the straightforward way:
In [15]: import numpy as np
In [16]: dt = np.dtype([('foo', int), ('bar', float)])
In [17]: r = np.zeros((3,3), dtype=dt)
Here is a (hopefully) simple question. If I create an array like this, how can I efficiently convert it to a record array which lets me do r.attr in addition to r['attr']. I'm pretty addicted to the former syntax.
In [32]: r2 = r.view(np.recarray)
In [33]: r2.foo Out[33]: array([[0, 0, 0], [0, 0, 0], [0, 0, 0]])
--
Robert Kern
"I have come to believe that the whole world is an enigma, a harmless enigma
that is made terrible by our own mad attempt to interpret it as though it had
an underlying truth."
-- Umberto Eco