I personally have always found it weird and annoying to deal with 0-D arrays, so +1 for scalars!*
*: admittedly, I have almost no grasp of the underlying NumPy implementation complexities, but I will happily take Sebastian's word that scalars can be consistent with the library.
Hi all,
When we create new datatypes, we have the option to make new choices
for the new datatypes [0] (not the existing ones).
The question is: Should every NumPy datatype have a scalar associated
and should operations like indexing return a scalar or a 0-D array?
This is in my opinion a complex, almost philosophical, question, and we
do not have to settle anything for a long time. But, if we do not
decide a direction before we have many new datatypes the decision will
make itself...
So happy about any ideas, even if its just a gut feeling :).
There are various points. I would like to mostly ignore the technical
ones, but I am listing them anyway here:
* Scalars are faster (although that can be optimized likely)
* Scalars have a lower memory footprint
* The current implementation incurs a technical debt in NumPy.
(I do not think that is a general issue, though. We could
automatically create scalars for each new datatype probably.)
Advantages of having no scalars:
* No need to keep track of scalars to preserve them in ufuncs, or
libraries using `np.asarray`, do they need `np.asarray_or_scalar`?
(or decide they return always arrays, although ufuncs may not)
* Seems simpler in many ways, you always know the output will be an
array if it has to do with NumPy.
Advantages of having scalars:
* Scalars are immutable and we are used to them from Python.
A 0-D array cannot be used as a dictionary key consistently [1].
I.e. without scalars as first class citizen `dict[arr1d[0]]`
cannot work, `dict[arr1d[0].item()]` may (if `.item()` is defined,
and e.g. `dict[arr1d[0].frozen()]` could make a copy to work. [2]
* Object arrays as we have them now make sense, `arr1d[0]` can
reasonably return a Python object. I.e. arrays feel more like
container if you can take elements out easily.
Could go both ways:
* Scalar math `scalar = arr1d[0]; scalar += 1` modifies the array
without scalars. With scalars `arr1d[0, ...]` clarifies the
meaning. (In principle it is good to never use `arr2d[0]` to
get a 1D slice, probably more-so if scalars exist.)
Note: array-scalars (the current NumPy scalars) are not useful in my
opinion [3]. A scalar should not be indexed or have a shape. I do not
believe in scalars pretending to be arrays.
I personally tend towards liking scalars. If Python was a language
where the array (array-programming) concept was ingrained into the
language itself, I would lean the other way. But users are used to
scalars, and they "put" scalars into arrays. Array objects are in some
ways strange in Python, and I feel not having scalars detaches them
further.
Having scalars, however also means we should preserve them. I feel in
principle that is actually fairly straight forward. E.g. for ufuncs:
* np.add(scalar, scalar) -> scalar
* np.add.reduce(arr, axis=None) -> scalar
* np.add.reduce(arr, axis=1) -> array (even if arr is 1d)
* np.add.reduce(scalar, axis=()) -> array
Of course libraries that do `np.asarray` would/could basically chose to
not preserve scalars: Their signature is defined as taking strictly
array input.
Cheers,
Sebastian
[0] At best this can be a vision to decide which way they may evolve.
[1] E.g. PyTorch uses `hash(tensor) == id(tensor)` which is arguably
strange. E.g. Quantity defines hash correctly, but does not fully
ensure immutability for 0-D Quantities. Ensuring immutability in a
world where "views" are a central concept requires a write-only copy.
[2] Arguably `.item()` would always return a scalar, but it would be a
second class citizen. (Although if it returns a scalar, at least we
already have a scalar implementation.)
[3] They are necessary due to technical debt for NumPy datatypes
though.
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