Re: [Numpy-discussion] lists of zeros and ones

On Fri, Mar 19, 2010 at 8:17 AM, Joe Kington <jkington@wisc.edu> wrote:

See itertools.permutations (python standard library) e.g. In [3]: list(itertools.permutations([1,1,0,0])) Out[3]: [(1, 1, 0, 0),  (1, 1, 0, 0),  (1, 0, 1, 0),  (1, 0, 0, 1),  (1, 0, 1, 0),  (1, 0, 0, 1),  (1, 1, 0, 0),  (1, 1, 0, 0),  (1, 0, 1, 0),  (1, 0, 0, 1),  (1, 0, 1, 0),  (1, 0, 0, 1),  (0, 1, 1, 0),  (0, 1, 0, 1),  (0, 1, 1, 0),  (0, 1, 0, 1),  (0, 0, 1, 1),  (0, 0, 1, 1),  (0, 1, 1, 0),  (0, 1, 0, 1),  (0, 1, 1, 0),  (0, 1, 0, 1),

 (0, 0, 1, 1),  (0, 0, 1, 1)] Hope that helps, -Joe

That treats each 1 as distinct. set() solves that:

...

list(set(itertools.permutations([1,1,0,0])))

[(1, 0, 1, 0), (1, 1, 0, 0), (0, 0, 1, 1), (1, 0, 0, 1), (0, 1, 1, 0), (0, 1, 0, 1)]