10 Feb
2009
10 Feb
'09
4:10 a.m.
On Mon, Feb 9, 2009 at 16:25, M Trumpis
I played around with a C translation of that test program, and found that dgesvd (but not dgesdd) happens to converge and return all non-negative singular values for both operators I was having trouble with. I'm also looking at the Octave code just now, and I think they're using dgesvd also. Any one know why numpy uses dgesdd? speed?
Yes. -- Robert Kern "I have come to believe that the whole world is an enigma, a harmless enigma that is made terrible by our own mad attempt to interpret it as though it had an underlying truth." -- Umberto Eco