I get the same result on 1.4.1

On Thu, Jul 22, 2010 at 1:00 PM, Johann Hibschman <jhibschman+numpy@gmail.com> wrote:
I'm trying to understand numpy.subtract.reduce.  The documentation
doesn't seem to match the behavior.  The documentation claims

 For a one-dimensional array, reduce produces results equivalent to:

 r = op.identity
 for i in xrange(len(A)):
    r = op(r,A[i])
 return r

However, numpy.subtract.reduce([1,2,3]) gives me 1-2-3==-4, not
0-1-2-3==-6.

Now, I'm on an older version (1.3.0), which might be the problem, but
which is "correct" here, the code or the docs?

Thanks,
Johann

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