27 Apr
2007
27 Apr
'07
1:47 p.m.
On Thu, 26 Apr 2007, Dan Christensen wrote:
Note also that double-precision reals are a subset of the rationals, since each double precision real is exactly representable as a rational number, but many rational numbers are not exactly representable as double precision reals. Not sure if this means that reals should be a subclass of the rationals.
Not quite all: the space of doubles include a small number of things that aren't representable by a rational (+/- inf, for instance). -- jan grant, ISYS, University of Bristol. http://www.bris.ac.uk/ Tel +44 (0)117 3317661 http://ioctl.org/jan/ Spreadsheet through network. Oh yeah.