What I am doing right now is: Set up a new matrix with one less row or column (zeros()), then copy all the rows/columns but the one I'd like to delete to the new matrix.
I haven't done any comparisons, but I suspect that Numeric.take() is faster for large arrays. Try this: def delete_row(matrix, row): return Numeric.take(matrix, range(row) + range(row+1, matrix.shape[0])) def delete_column(matrix, column): return Numeric.take(matrix, range(column) + range(column+1, matrix.shape[1]), axis = 1) Konrad. -- ------------------------------------------------------------------------------- Konrad Hinsen | E-Mail: hinsen@cnrs-orleans.fr Centre de Biophysique Moleculaire (CNRS) | Tel.: +33-2.38.25.56.24 Rue Charles Sadron | Fax: +33-2.38.63.15.17 45071 Orleans Cedex 2 | Deutsch/Esperanto/English/ France | Nederlands/Francais -------------------------------------------------------------------------------