22/11/10 @ 11:08 (-0800), thus spake Christopher Barker:

On 11/21/10 11:37 AM, Ernest AdroguĂ© wrote:

so you want

t[:,x,y]

I tried that, but it's not the same:

In [307]: t[[0,1],x,y] Out[307]: array([1, 7])

In [308]: t[:,x,y] Out[308]: array([[1, 3], [5, 7]])

what is your t? Here's my example, which I think matches what you asked for:

In [1]: import numpy as np

In [2]: a = np.arange(12)

In [3]: a.shape = (3,2,2)

In [4]: a Out[4]: array([[[ 0, 1], [ 2, 3]],

`[[ 4, 5], [ 6, 7]], [[ 8, 9], [10, 11]]])`

In [5]: a[:,1,0] Out[5]: array([ 2, 6, 10])

This works with scalar indices, but not with arrays. The problem is that I don't want always the same element from each subarray, but an arbitrary element, say the (1,0) from the first, the (0,0) from the second, and so on, so I have to use arrays.