Re: [Numpy-discussion] trivial question: how to compare dtype - but ignoring byteorder ?

Sebastian Haase wrote:

Hi, if I have a numpy array 'a' and say: a.dtype == numpy.float32

Is the result independent of a's byteorder ? (That's what I would expect ! Just checking !)

I think I misread the question and saw "==" as "=" But, the answer I gave should still help: the byteorder is a property of the data-type. There is no such thing as "a's" byteorder. Thus, numpy.float32 (which is actually an array-scalar and not a true data-type) is interepreted as a machine-byte-order IEEE floating-point data-type with 32 bits. Thus, the result will depend on whether or not a.dtype is machine-order or not. -Travis