Oct. 11, 2011
6 p.m.
Hi, Can anyone think of a clever way to round an integer to the next lowest integer represented in a particular floating point format? For example: In [247]: a = 2**25+3 This is out of range of the continuous integers representable by float32, hence: In [248]: print a, int(np.float32(a)) 33554435 33554436 But I want to round down (floor) the integer in float32. That is, in this case I want:
floor_exact(a, np.float32) 33554432
I can break the float into its parts to do it: https://github.com/matthew-brett/nibabel/blob/f687bfc88d1676a09fc76c968a346b... but that's obviously rather ugly... Is there a simpler way? I'm sure there is and I haven't thought of it... Best, Matthew