Re: [Numpy-discussion] sample without replacement

On Mon, Dec 20, 2010 at 11:28 AM, Alan G Isaac <alan.isaac@gmail.com> wrote:

I want to sample *without* replacement from a vector (as with Python's random.sample).  I don't see a direct replacement for this, and I don't want to carry two PRNG's around.  Is the best way something like  this?

       permutation(myvector)[:samplesize]

python has it in random sample( population, k) Return a k length list of unique elements chosen from the population sequence. Used for random sampling without replacement. New in version 2.3 Josef

Thanks, Alan Isaac _______________________________________________ NumPy-Discussion mailing list NumPy-Discussion@scipy.org http://mail.scipy.org/mailman/listinfo/numpy-discussion