Even knowing that, it's still confusing that round(np.float64(0.0))
isn't the same as round(0.0). The reason is a Python 2 / Python 3
thing: in Python 2, round returns a float, while on Python 3, it
returns an integer – but numpy still uses the python 2 behavior
everywhere.
I'm not sure if it's possible or worthwhile to change this. If we'd
changed it when we first added python 3 support then it would have
been easy (and obviously a good idea), but at this point it might be
tricky?
-n
On Thu, Mar 22, 2018 at 12:32 PM, Nathan Goldbaum
numpy.float is an alias to the python float builtin.
https://github.com/numpy/numpy/issues/3998
On Thu, Mar 22, 2018 at 2:26 PM Olivier
wrote: Hello,
Is it normal, expected and desired that :
round(numpy.float64(0.0)) is a numpy.float64
while
round(numpy.float(0.0)) is an integer?
I find it disturbing and misleading. What do you think? Has it already been discussed somewhere else?
Best regards,
Olivier
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