Hi Mr. Goodman Thanks a lot. Works Fine Reagards Mario Moura 2010/12/27 Keith Goodman <kwgoodman@gmail.com>:
On Mon, Dec 27, 2010 at 10:36 AM, Mario Moura <moura.mario@gmail.com> wrote:
Hi Folks
a = np.zeros((4,3,5,55,5),dtype='|S8') myLen = 4 # here I use myLen = len(something) li = [3,2,4] # li from a list.append(something) sl = slice(0,myLen) tmpIndex = tuple(li) + sl + 4 # <== Here my problem a[tmpIndex]
# So What I want is: fillMe = np.array(['foo','bar','hello','world']) # But I cant contruct by hand like this a[3,2,4,:4,4] = fillMe a
Again. I need construct custom slice from here tmpIndex = tuple(li) + sl + 4 a[tmpIndex]
First let's do it by hand:
a = np.zeros((4,3,5,55,5),dtype='|S8') fillMe = np.array(['foo','bar','hello','world']) a[3,2,4,:4,4] = fillMe
Now let's try using an index:
b = np.zeros((4,3,5,55,5),dtype='|S8') myLen = 4 li = [3,2,4] sl = slice(0,myLen)
Make index:
idx = range(a.ndim) idx[:3] = li idx[3] = sl idx[4] = 4 idx = tuple(idx)
Compare results:
b[idx] = fillMe (a == b).all() True
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