wait, nevermind. your're right. Thanks!
On Sun, May 3, 2009 at 6:30 PM, Chris Colbert

but this gives me just the locations of the column/row maximums.

I need the (x,y) location of the array maximum.

Chris

On Sun, May 3, 2009 at 4:34 PM,

wrote: On Sun, May 3, 2009 at 3:30 PM, Chris Colbert

wrote: my case is only for 2d, but should apply to Nd as well.

It would be convienent if np.max would return a tuple of the max value and its Nd location indices.

Is there an easier way than just using the 1d flattened array max index (np.argmax) and calculating its corresponding Nd location?

factors = np.random.randint(5,size=(4,3)) factors array([[1, 1, 3], [0, 2, 1], [4, 4, 1], [2, 2, 4]]) factors.max() 4 np.argmax(factors) 6 np.nonzero(factors==factors.max()) (array([2, 2, 3]), array([0, 1, 2]))

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