converting 1 dimensional array to 2 dimensional array
Hi All, I know how to reshape arrays, my problem is a little more complicated than that. I am looking for the most efficient way to do the following and an example will help: 1) I have a an array of bytes b = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12] This bytes array represents a width of 2 and a height of 3. Each 2 bytes in that bytes array makes an unsigned 16 bit integer. 2) I want to get the following 2 dimensional array from the bytes array where each item in the two dimensional array is an unsigned 16 bit integer something like: [ [(1,2) , (3,4)], [(5,6) , (7,8)], [(9,10) , (11,12)] ] in the first row there are 2 elements each one is made of 2 bytes from the bytes array etc... meaning that (1, 2) = b[0] + b[1] << 8 (3, 4) = b[2] + b[3] << 8 ... ... What is the most efficient way to achieve that with numpy ? Thanks 0L [1] << 8 ,[2], [3, 4]
participants (2)
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Juan Nunez-Iglesias
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Omry Levy