If I have a character array t:

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t = array(['abcd','aacd','ddfa','qqcd']) print t [[a b c d] [a a c d] [d d f a] [q q c d]]

What's the most efficient way to create an array that contains the indexes of the rows that match a particular pattern. If I want to match a 'c' in the third column, I'd like the array to look like this: i = array([0,1,3]) Thanks, Sam ----- End forwarded message -----