simple way to denote unchanged dimension in reshape?
Dear all, I have a simple question. Is there a way to denote the unchanged dimension in the reshape function? like suppose I have an array named "arr" having three dims with the first dimension length as 48, I want to reshape the first dim into 12*4, but keeping all the other dimension length unchanged. like when we slice the array, we can use: arr[10:40, ... ], "...' represents all remaining dimesions. however when doing reshape, we must use: arr.reshape(12,-1,arr.shape(1),arr.shape(2)) Is there something allowing more flexible reshape, like: arr.reshape(12,-1,...)? thanks a lot in advance, best, Chao -- please visit: http://www.globalcarbonatlas.org/ *********************************************************************************** Chao YUE Laboratoire des Sciences du Climat et de l'Environnement (LSCE-IPSL) UMR 1572 CEA-CNRS-UVSQ Batiment 712 - Pe 119 91191 GIF Sur YVETTE Cedex Tel: (33) 01 69 08 29 02; Fax:01.69.08.77.16 ************************************************************************************
Chao YUE <chaoyuejoy <at> gmail.com> writes:
Dear all, I have a simple question. Is there a way to denote the unchanged dimension
in the reshape function? like suppose I have an array named "arr" having three dims with the first dimension length as 48, I want to reshape the first dim into 12*4, but keeping all the other dimension length unchanged.
like when we slice the array, we can use: arr[10:40, ... ], "...'
represents all remaining dimesions.
however when doing reshape, we must use:
arr.reshape(12,-1,arr.shape(1),arr.shape(2))
Is there something allowing more flexible reshape, like:
arr.reshape(12,-1,...)?
thanks a lot in advance,best,
Chao
For the example given the below code works: In [1]: x = randn(48,5,4,3,2) In [2]: x.reshape(12,-1,*x.shape[1:]).shape Out[2]: (12L, 4L, 5L, 4L, 3L, 2L) HTH, Dave
Oh, I didn't think it out. thanks. Chao On Thu, May 29, 2014 at 11:59 AM, Dave Hirschfeld <dave.hirschfeld@gmail.com
wrote:
Chao YUE <chaoyuejoy <at> gmail.com> writes:
Dear all, I have a simple question. Is there a way to denote the unchanged
dimension in the reshape function? like suppose I have an array named "arr" having three dims with the first dimension length as 48, I want to reshape the first dim into 12*4, but keeping all the other dimension length unchanged.
like when we slice the array, we can use: arr[10:40, ... ], "...'
represents all remaining dimesions.
however when doing reshape, we must use:
arr.reshape(12,-1,arr.shape(1),arr.shape(2))
Is there something allowing more flexible reshape, like:
arr.reshape(12,-1,...)?
thanks a lot in advance,best,
Chao
For the example given the below code works:
In [1]: x = randn(48,5,4,3,2)
In [2]: x.reshape(12,-1,*x.shape[1:]).shape Out[2]: (12L, 4L, 5L, 4L, 3L, 2L)
HTH, Dave
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-- please visit: http://www.globalcarbonatlas.org/ *********************************************************************************** Chao YUE Laboratoire des Sciences du Climat et de l'Environnement (LSCE-IPSL) UMR 1572 CEA-CNRS-UVSQ Batiment 712 - Pe 119 91191 GIF Sur YVETTE Cedex Tel: (33) 01 69 08 29 02; Fax:01.69.08.77.16 ************************************************************************************
participants (2)
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Chao YUE -
Dave Hirschfeld