On Wed, Oct 6, 2010 at 5:26 AM, Chris Withers <chris@simplistix.co.uk>wrote:

Hi All,

Given an array such as:

array([0, 1, 2, 3, 4, 5, 6, 7, 8, 9])

How can I find the index of a particular number in the array?

(ie: if it was a list, I'd do [1,2,3,4].index(3))

cheers,

Chris _______________________________________________ NumPy-Discussion mailing list NumPy-Discussion@scipy.org http://mail.scipy.org/mailman/listinfo/numpy-discussion

Try with numpy.where(array == value) and plain "array == value" IIRC, the first will return an array the size of the found elements and the second will return an array (or list?) of True/False. Either can be used as "index = numpy.where()" and "index = (array == value)" and then "array[index]". N

Chris, You can use where() command to find index of a particular number in the array. For e.g. to find index of number 1 in array a, you can say idx = where(a==1) Regards, Brian -----Original Message----- From: numpy-discussion-bounces@scipy.org [mailto:numpy-discussion-bounces@scipy.org] On Behalf Of Chris Withers Sent: Wednesday, October 06, 2010 5:27 AM To: numpy-discussion@scipy.org Cc: snezana.pejic@glcuk.com Subject: [Numpy-discussion] index of a value in an array Hi All, Given an array such as: array([0, 1, 2, 3, 4, 5, 6, 7, 8, 9]) How can I find the index of a particular number in the array? (ie: if it was a list, I'd do [1,2,3,4].index(3)) cheers, Chris _______________________________________________ NumPy-Discussion mailing list NumPy-Discussion@scipy.org http://mail.scipy.org/mailman/listinfo/numpy-discussion