Also, there is a "non-method" way: the .T property:

...

...

a = np. matrix([[1,2,3],[4,5,6],[7,8,9]]) a matrix([[1, 2, 3], [4, 5, 6], [7, 8, 9]]) b = a.T b matrix([[1, 4, 7], [2, 5, 8], [3, 6, 9]])

DG --- On Mon, 7/6/09, Chris Colbert wrote:

From: Chris Colbert Subject: Re: [Numpy-discussion] transpose of a matrix should be another matrix To: "Discussion of Numerical Python" Date: Monday, July 6, 2009, 10:42 PM you actually have to call the method as transpose(). What you requested was the actual method.

...

...

...

import numpy as np a = np. matrix([[1,2,3],[4,5,6],[7,8,9]]) a matrix([[1, 2, 3],

        [4, 5, 6],         [7, 8, 9]])

...

...

...

b = a.transpose() b matrix([[1, 4, 7],         [2, 5, 8],         [3, 6, 9]])

On Tue, Jul 7, 2009 at 1:34 AM, Dr. Phillip M. Feldman wrote:

I'm using the Enthought Python Distribution. When I define a matrix and

transpose it, it appears that the result is no longer a matrix (see below).

This is both surprising and disappointing.  Any suggestions will be

appreciated.

In [16]: A=matrix([[1,2,3],[4,5,6],[7,8,9]])

In [17]: B=A.transpose

In [18]: A

Out[18]:

matrix([[1, 2, 3],

       [4, 5, 6],

       [7, 8, 9]])

In [19]: B

Out[19]:

--

View this message in context: http://www.nabble.com/transpose-of-a-matrix-should-be-another-matrix-tp24367...

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