On Mon, 11 May 2009 15:03:02 +0200 Sebastien Binet wrote:

On Monday 11 May 2009 14:36:17 Nils Wagner wrote:

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On Mon, 11 May 2009 14:25:46 +0200

Francesc Alted wrote:

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A Monday 11 May 2009, Nils Wagner escrigué:

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Hi all,

Please consider two strings

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> line_a

'12345678abcdefgh12345678'

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> line_b

'12345678 abcdefgh 12345678'

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> line_b.split()

['12345678', 'abcdefgh', '12345678']

Is it possible to split line_a such that the output is

['12345678', 'abcdefgh', '12345678']

Mmh, your question is a bit too generic.

Indeed. I would like to split strings made of digits after eight characters each.

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line_a

'111111.1222222.2333333.3'

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line_b

'111111.1 222222.2 333333.3'

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line_b.split()

['111111.1', '222222.2', '333333.3']

How can I accomplish that ? would this suit you ?

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np.asarray(line_b,dtype=[('hdr','|S8'),('mid','|S8'),('tail','|S8')]) array(('111111.1', '222222.2', '333333.3'), dtype=[('hdr', '|S8'), ('mid', '|S8'), ('tail', '|S8')])

hth, sebastien. -- ######################################### # Dr. Sebastien Binet # Laboratoire de l'Accelerateur Lineaire # Universite Paris-Sud XI # Batiment 200 # 91898 Orsay #########################################

here is my workaround. from numpy import arange line_a = '111111.1222222.2333333.3' # without separator line_b = '111111.1 222222.2 333333.3' # including space as a delimiter div, mod = divmod(len(line_a),8) liste = [] for j in arange(0,div): liste.append(line_a[j*8:(j+1)*8]) print liste print line_b.split() # Works for line_b but not for line_a Cheers, Nils