Hello again, I have forgotten in my previous mail that I want the procedure to run independent of the value of N... So the value of N is not known during the implementation. Sorry about the duplication...

Hello!

I have a N-dimensional array A and I want to operate in one of the axis (k) with a 1 dimensional array (for instance, subtracting an array B of length k). I have looked for some solutions in the manual and did not found any.

So after testing a lot I found following solution:

A=Numeric.array(a)

A.shape=(a1,a2,...,ak,...,aN) #where N is any int value

B=Numeric.array(b) B.shape=(ak,)

A_modified=Numeric.reshape(A, (a1*a2*...*aN,ak)) #ak is not included in the product

result=[] for i in A_modified: result.append(i - B)

and finally reshaping the result appropriately. But it does not seem neither elegant nor simple.

Is there any more elegant solution? The key point is: how to operate a N-D array with a 1D in one determined axis?

Thanks in advance. Regards, Aureli

################################# Aureli Soria Frisch Fraunhofer IPK Dept. Pattern Recognition post: Pascalstr. 8-9, 10587 Berlin, Germany e-mail:aureli@ipk.fhg.de fon: +49 30 39 00 61 50 fax: +49 30 39 17 517 #################################