Forget it. N.isnan() does the job. YVES On Mon, Oct 30, 2006 at 11:47:57AM +0100, Yves wrote:

Hi,

Is there a way of checking for nan's in an array, as comparing to N.nan doesn't seem to work.

In [1]: import numpy as N

In [2]: a = N.asarray(0.)/0 Warning: invalid value encountered in divide

In [3]: a Out[3]: nan

In [4]: a==N.nan Out[4]: False

In [5]: b = a.copy()

In [6]: a==b Out[6]: False

In [7]: b Out[7]: nan

In [8]: N.__version__ Out[8]: '1.0.dev3390'

Many thanks, YVES

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