The "I" dtype character
dtype('i1')
dtype('I1')
Hi, is it intentional that "I" is supported as a dtype character, but cannot be suffixed with a size? dtype('int8') dtype('uint32') I know "u" is documented as unsigned integer, but this seems an unnecessary restriction that is confusing. thanks, Georg
Am 08.04.2013 09:14, schrieb Georg Brandl:
Hi,
is it intentional that "I" is supported as a dtype character, but cannot be suffixed with a size?
dtype('i1') dtype('int8') dtype('I1') dtype('uint32')
I know "u" is documented as unsigned integer, but this seems an unnecessary restriction that is confusing.
Looking at the code, I see now that using "I2" raises a DeprecationWarning anyway, which is fair enough. Georg
On Mon, Apr 8, 2013 at 8:14 AM, Georg Brandl <g.brandl@gmx.net> wrote:
Hi,
is it intentional that "I" is supported as a dtype character, but cannot be suffixed with a size?
dtype('i1') dtype('int8') dtype('I1') dtype('uint32')
"i" means "integer". "i1" means "integer with 8 bits". "I" means "32-bit unsigned integer". "I1" means "32-bit unsigned integer with 8 bits". Obviously this last thing doesn't make much sense :-). Historically numpy as accepted it anyway, and just ignored the suffix. In current numpy it's still allowed for backwards compatibility, but deprecated, and will become an error at some point. See https://github.com/numpy/numpy/issues/294 -n
participants (2)
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Georg Brandl -
Nathaniel Smith