On Sun, Dec 4, 2011 at 5:30 AM, Didrik Pinte <dpinte@enthought.com> wrote:

On Sun, Dec 4, 2011 at 6:11 AM, Warren Weckesser <warren.weckesser@enthought.com> wrote:

...

In numpy 1.6.1, what's the most straightforward way to convert a datetime64 to a python datetime.datetime? E.g. I have

In [1]: d = datetime64("2011-12-03 12:34:56.75")

In [2]: d Out[2]: 2011-12-03 12:34:56.750000

I want the same time as a datetime.datetime instance. My best hack so far is to parse repr(d) with datetime.datetime.strptime:

In [3]: import datetime

In [4]: dt = datetime.datetime.strptime(repr(d), "%Y-%m-%d %H:%M:%S.%f")

In [5]: dt Out[5]: datetime.datetime(2011, 12, 3, 12, 34, 56, 750000)

That works--unless there are no microseconds, in which case ".%f" must be removed from the format string--but there must be a better way.

Warren

Warren,

You can do that :

In [13]: a = array(["2011-12-03 12:34:56.75"], dtype=datetime64)

In [14]: b = a.astype(object)

In [15]: b[0] Out[15]: datetime.datetime(2011, 12, 3, 12, 34, 56, 750000)

Not sure how efficient it is but it works fine.

-- Didrik

Thanks, Didrik, that's just what I needed. Warren