numpy.fftpack: axis=None ?
Folks, I was playing around the numpy.fftpack when I ran into the problem below: it seems that axis=None is not valid with fft. Is there a reason for that ? I was assuming a behavior similar to other functions, where axis=None translates to "use a flat array".
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N.fft.fft(N.arange(100).reshape(10,10),128,None)
/usr/lib64/python2.4/site-packages/numpy/fft/fftpack.py in fft(a, n, axis) 85 different n's.""" 86 ---> 87 return _raw_fft(a, n, axis, fftpack.cffti, fftpack.cfftf, _fft_cache) 88 89
/usr/lib64/python2.4/site-packages/numpy/fft/fftpack.py in _raw_fft(a, n, axis, init_function, work_function, fft_cache) 44 fft_cache[n] = wsave 45 ---> 46 if a.shape[axis] != n: 47 s = list(a.shape) 48 if s[axis] > n:
TypeError: tuple indices must be integers -------------------------------------------------
PGM wrote:
Folks, I was playing around the numpy.fftpack when I ran into the problem below: it seems that axis=None is not valid with fft. Is there a reason for that ?
Not really, other than history and the fact that sub-packages of NumPy will often define their own behavior.
Perhaps we could implement it, but would this create more confusion as usually when axis=None is accepted then it is the default.
-Travis
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PGM -
Travis Oliphant