or, you can either use fill. In [53]: M = numpy.matrix(numpy.zeros((3,5))) In [55]: M.fill(999) In [56]: M Out[56]: matrix([[ 999., 999., 999., 999., 999.], [ 999., 999., 999., 999., 999.], [ 999., 999., 999., 999., 999.]]) L. On 12/21/07, devnew@gmail.com <devnew@gmail.com> wrote:

hi i am a beginner with numpy and python,so pardon me if this doubt seems silly i want to create a matrix with say 3 rows and 5 columns..and then set the values of each item in it .for this i did something like below

myarray=zeros((3,5)) #then set the items for row in range(3): for col in range(5): myarray[row][col]=999999.9999

mymatrix=matrix(myarray)

is this the way to do the matrix creation and value setting? is the use of zeros() unnecessary? i am in the early learning stage so your reply wd help me much

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