Elementwise provides helpful proxy objects which let you perform a series of computations on every element of an iterable or graph, in a lazy manner. Docs: http://packages.python.org/elementwise/ GitHub: https://github.com/nathan-rice/Elementwise Examples: The standard ElementwiseProxy: >>> nums = ElementwiseProxy([1, 2, 3, 4) >>> print nums.bit_length() 1, 2, 2, 3 >>> nums + 1 2, 3, 4, 5 >>> print nums * 2 2, 4, 6, 8 >>> print nums == 2 False, True, False, False >>> print ((nums + 1) * 2 + 3).apply(float) 7.0, 9.0, 11.0, 13.0 >>> print (nums.apply(float) + 0.0001).apply(round, 2) 1.0, 2.0, 3.0, 4.0 >>> print abs(nums - 3) 2, 1, 0, 1 >>> print (nums * 2 + 3) / 4 >>> print efoo2.undo(3) 1, 2, 3, 4 >>> print ((nums * 2 + 3) / 4).replicate([2, 2, 3, 3]) 1, 1, 2, 2 >>> words = ElementwiseProxy(["one", "two", "three", "four"]) >>> print (words + " little indians").upper().split(" ").apply(reversed).apply("_".join) * 2 'INDIANS_LITTLE_ONEINDIANS_LITTLE_ONE', 'INDIANS_LITTLE_TWOINDIANS_LITTLE_TWO', 'INDIANS_LITTLE_THREEINDIANS_LITTLE_THREE', 'INDIANS_LITTLE_FOURINDIANS_LITTLE_FOUR' The PairwiseProxy: >>> nums = PairwiseProxy([1, 2, 3, 4]) >>> nums + [1, 2, 3, 4] 2, 4, 6, 8 >>> nums * [2, 2, 3, 3] 2, 4, 9, 12 >>> nums == [2, 2, 3, 5] False, True, True, False >>> (nums.apply(float) / itertools.count(2) + itertools.count(1)).apply(round, args=itertools.repeat([2])) 1.5, 2.67, 3.75, 4.8 >>> abs(nums - [3, 2, 1, 1]) 2, 0, 2, 3 >>> (nums * [2, 2, 1, 5] + [3, 5, 9, 0]) / [4, 1, 2, 3] 1, 9, 6, 6 >>> ((nums * itertools.repeat(2) + itertools.repeat(3)) / itertools.repeat(4)).replicate([2, 2, 3, 3]) 1, 0, 0, 0 >>> ((nums * [2, 3, 4, 5]) > [5, 6, 7, 8]) != [True, True, False, True] True, True, True, False The RecursiveElementwiseProxy: >>> treenums = RecursiveElementwiseProxy([[1, 2, 3], [4, 5, 6], [7, 8, 9]]) >>> treenums + 1 ((2, 3, 4), (5, 6, 7), (8, 9, 10)) >>> treenums * 2 ((2, 4, 6), (8, 10, 12), (14, 16, 18)) >>> (treenums * 2 + 1).apply(float) ((3.0, 5.0, 7.0), (9.0, 11.0, 13.0), (15.0, 17.0, 19.0)) Feedback is welcome.